Structural Similarities for the Entities in PDB 4DX9
The following structural similarities have been found using the jFATCAT-rigid algorithm [1,2]. To reduce the number of hits, a 40% sequence identity clustering has been applied and a representative chain taken from each cluster. If the representative chain consists of multiple domains, each domain is included in the search. If available, the SCOP 1.75 domain assignment  is used. Otherwise algorithmic domain assignments are computed using the ProteinDomainParser .
Entity #1: Chains: 0,1,2,3,4,5,A,C,E,G,I,K,M,O,Q,S,U,W,Y,a,c,e,g,i,k,m,o,q,s,u,w,y
No structure alignment results are available for 4DX9.0, 4DX9.1, 4DX9.2, 4DX9.3, 4DX9.4, 4DX9.5, 4DX9.A, 4DX9.C, 4DX9.E, 4DX9.G, 4DX9.I, 4DX9.K, 4DX9.M, 4DX9.O, 4DX9.Q, 4DX9.S, 4DX9.U, 4DX9.W, 4DX9.Y, 4DX9.a, 4DX9.c, 4DX9.e, 4DX9.g, 4DX9.i, 4DX9.k, 4DX9.m, 4DX9.o, 4DX9.q, 4DX9.s, 4DX9.u, 4DX9.w, 4DX9.y explicitly.
These chains are represented by chain 4JIF.A which is 100% sequence identical.
Entity #2: Chains: 6,7,8,9,B,D,F,H,J,L,N,P,R,T,V,X,Z,b,d,f,h,j,l,n,p,r,t,v,x,z
This entity is too short to be considered for the all vs. all structure alignments.
Calculate pairwise sequence or structure alignments.
A detailed description of the procedure for the all vs. all alignments is available.