Structural Similarities for the Entities in PDB 3KLF

The following structural similarities have been found using the jFATCAT-rigid algorithm [1,2].

To reduce the number of hits, a 40% sequence identity clustering has been applied and a representative chain taken from each cluster. If the representative chain consists of multiple domains, each domain is included in the search. If available, the SCOP 1.75 domain assignment [3] is used. Otherwise algorithmic domain assignments are computed using the ProteinDomainParser [4].

Currently viewing only significant results (P-value < 0.001). Show all available results.

Cluster data are up-to-date as of: Sep-20-2016

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A detailed description of the procedure for the all vs. all alignments is available.

Entity #1 | Chains A,E,I,M

Description: Reverse transcriptase/ribonuclease H protein | Length: 557

No structure alignment results are available for 3KLF.A, 3KLF.E, 3KLF.I, 3KLF.M explicitly.

These chains are represented by chain 4G1Q.A which has more than 95% sequence identity.

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View how chain 3KLF.M compares with the representative chain PDP:4G1QAa. Select a comparison method:


Entity #2 | Chains B,F,J,N

Description: p51 RT protein | Length: 444

No structure alignment results are available for 3KLF.B, 3KLF.F, 3KLF.J, 3KLF.N explicitly.

These chains are represented by chain 4G1Q.B which is 100% sequence identical.

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View how chain 3KLF.N compares with the representative chain PDP:4G1QBa. Select a comparison method:


Entity #3 | Chains C,G,K,O

Description: DNA (5'-D(*AP*T*GP*CP*AP*TP*GP*GP*CP*GP*CP*CP*CP*GP*AP*AP*CP*AP*GP*GP*GP*AP*CP*TP*GP*TP*G)-3') dna | Length: 27

This entity is NOT a polypeptide entity and therefore cannot be considered for the all vs. all structure alignments.


Entity #4 | Chains D,H,L,P

Description: DNA (5'-D(*A*CP*AP*GP*TP*CP*CP*CP*TP*GP*TP*TP*CP*GP*GP*(MRG)P*CP*GP*CP*CP*(2DA))-3') dna | Length: 21

This entity is NOT a polypeptide entity and therefore cannot be considered for the all vs. all structure alignments.


References